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1.
一元二次方程的公共根问题,是一种常见的题型,但同学们在解此类问题时,常感到棘手.为此,本文通过举例向同学们介绍此类问题的几种常用解法,供大家学习时参考.一、作差求根法对于比较简单的两个一元二次方程有公共根的问题,可采用作差求根法来解决.方法是:把两个方程相减(或相加)消去二次项,由所得一元一次方程来确定未知系数的值,进而求出方程的根.例1m为何值时,方程x2+mx-3=0与方程x2-4x-(m-1)=0有~公共实数根?并求此根.解将已知两方程相减,得(m+4)X=-(m-4).当m=-4时,公共根不存在;当m4时,公共…  相似文献   

2.
一元二次方程的公报问题,在各地中考和数学竞赛中经常见到一这类题型的解法一般都可以把两个方程作差,消去二次项后,运用方程理论进行讨论求解.请看下面例谈.例1若关于x的方程x’-。+2=0……①与x’,(m十回)。+m=0……②有一个相同的实数根,则m的值为()(96年山东中考题)(A)3;阳广;(C)4;(D)一上解两方程作差,消去二次项,即①-②得一。+(m+l)x+2-m=0.整理得。=m-2……③③代人①,得(m-2)’-m(m-2)+2=0.解之,得m=3.当m=3时,凸l>0,凸。>0符合题意故选(A).例2m为何值时,方程x…  相似文献   

3.
膜法SBR工艺对生活污水N、P降解的研究   总被引:3,自引:0,他引:3  
研究了膜法SBR工艺在不同操作条件下对生活污水N、P的降解效果,当污泥浓度一定,水中DO达到3.5mg/L时,水质pH及无机C源是影响NH3-N降解的关键。当进水NH3-N浓度在50-105mg/L,COD浓度在120-260mg/L时,用Na2CO3调pH在8.0-8.4,运行工况为:进水-闲置段0.5h,曝气1.5h、沉降1h时,可使COD达标排放,NH3-N去除率在50-70%,且有最佳脱N效果。  相似文献   

4.
一、一元一次方程的定义只含有一个未知数,且未知数的最高次数是2的整式方程叫做一元二次方程,其一般形式是一’+bC半C—0(。学0).注意。学0是一元二次方程的一个重要隐含条件,解有关一元二次方程的问题时,必须挖掘和应用这个隐含条件.否则将会导致谬误.例1当m时,关于x的方程(m‘-3m+2)x’+(m-2)x+7—0是一元二次方程.解由一元二次方程的定义知,当m‘-3mWe2-0时,即mwtl且m-2时,(m‘一3m+2)x’+(m-2)x+7—0是一元H次方程.二、一无二次方程的解法解一元二次方程的基本方法有:(1)直接开平方法;(2)…  相似文献   

5.
建立采用涡旋辅助浊点萃取滇重楼提取物中4个偏诺皂苷类成分,以非离子表面活性剂脂肪醇聚氧乙烯醚 AEO -9为萃取剂,V(乙腈)∶V(水)=38∶62为流动相,对富集的偏诺皂苷进行高效液相色谱快速分离的方法.最优实验条件为,AEO -9用量为110μL,正戊酸用量为150μL,pH 为9,平衡温度为40℃,平衡时间为15 min.结果表明,检测出滇重楼中4个偏诺皂苷 VI,VII,Pa 及 H 的质量分数分别为0.9923%,1.3603%,3.3444%及1.6663%,检测限达3.2~4.0μg/L,RSD 低于0.5%,定量限为6.6~8.3μg/L,线性范围为10~500μg/L,萃取的富集倍数达到23倍,萃取的回收率为98.68%~102.46%.  相似文献   

6.
目的:分析玉米成熟期籽粒胚乳淀粉粒度分布特征与淀粉黏度参数间关系。方法:以华皖681(HW681)等7个玉米品种为材料,分析成熟期玉米籽粒胚乳淀粉粒度分布特征与黏度参数。结果:成熟期玉米籽粒淀粉粒体积、数目、表面积分布分别呈双峰、单峰与双峰曲线,其中体积分布曲线峰值出现在1.5、16μm左右,低谷值出现在3μm左右。以3、16μm为界限,将玉米胚乳淀粉粒分为小型(粒径3μm)淀粉粒、中型(粒径3~16μm)淀粉粒与大型(粒径16μm)淀粉粒。玉米小型、中型与大型淀粉粒体积百分比分别为9.29%~10.35%、44.47%~8.05%和31.8%~46.25%;小型淀粉粒数目百分比99.5%以上,中、大型淀粉粒仅占0.5%。可见虽然小淀粉粒体积百分比较小,但玉米胚乳淀粉粒绝大多数是由粒径3μm小淀粉粒组成。不同品种淀粉黏度参数存在显著差异。中、小型淀粉粒体积百分比与淀粉峰值黏度、稀懈值呈显著或极显著负相关,大型淀粉粒体积百分比与淀粉峰值黏度、稀懈值呈显著或极显著正相关。结论:与中、小型淀粉粒相比,玉米成熟期籽粒胚乳中大型淀粉粒峰值黏度、稀懈值较高。  相似文献   

7.
采用加热回流提取法提取当归龙荟丸中的阿魏酸,并利用色谱柱Agilent C18(4.0·125mm,5.0μm),以甲醇-3%冰醋酸溶液(20:80)为流动相,流速1、0mL/min,柱温:25℃,测定波长:320nm.测定阿魏酸在0.2116-3.174μg范围内线性关系良好(r=0.9995),平均回收率96.7%,RSD=0.4%.  相似文献   

8.
一、填空题(每空3分,共54分);1.方程x2=5x的解是;2方程x2-2x-4=0的解是;3.方程x4-5x2-6=0的解是;4方程的解是;5方程“’”“一【十3,’-2“””“—儿,s.方程xtwsx+/7河南一ti的解是、;6方程X’一2人一8一0的解是、;7不等式K一2。>3的解集是;8.不等式X’一4x-12<0的解集是9.不等式军二<l冬的非负整数解是;”“一3~3”“”「”“”’”“”10.若关于工的方程m’x’+(Zm+l)x+l—0有两个不等实根,则m的取值范围是;11.已知方程(m-1)x’+2(m-l)x+2(。+3)一0,当m一时,方程有两个相等实…  相似文献   

9.
应用薄层扫描法测定孩儿茶中消旋儿茶素的含量,方法简便,重现性好,结果准确。在4.0-8.0μg/ml范围内呈线性关系,r=0.9992。回收率为99.6%-102.8%,RSD为1.2%-4.2%。  相似文献   

10.
一、填空题1.已知代数式9-3a,当a____时,它的值大于零;当a时,它的值小于零.(1994年.河南)2.当a时,一元一次不等式ax+3>0的解集为x>(1988年,西藏)3.如果关于x的方程(1-m)x=1-2x的解是一个负数,那么m的取值范围是(1989年.山东)4.不等式的非负整数解为(1992年,山西)5.求不等式的正整数解为.(1989年,贵阳)6.不等式组的解集是(1993年,甘肃)7.不等式组的解集是(1994年,四川)二、选择题1.使代数式的值为非负整数的m的取值中,最大的一个是(A)0;(B)4;(C)-2;(D)2.(1994年,四川)2.…  相似文献   

11.
《海外英语》2007,(5):44-45
It is worthy of noting that, whilst Crookston Castle witnessed the earlier and happier portion of Mary's variegated life,  相似文献   

12.
一、吃和喝吃苹果 eat an apple, 吃药 take medicine,吃糖 have some sweets,吃饭 have one's meals,吃馆子 dine out,吃惊 be surprised/  相似文献   

13.
《海外英语》2007,(5):10-11
Many college freshmen arrive woefully unprepared to do college work, and as disadvantaged populations continue to grow, the share of the American work force that has made it through college is expected to plummet. Many experts blame that educational failure not just on high schools but also on colleges. School & College, a special report by The Chronicle, looks at efforts to fix the system. What reforms would better prepare students for college? What should schools and colleges be doing differently? How should state and federal officials help?  相似文献   

14.
《海外英语》2007,(4):36
There are numbers of crossroads on our long and unpredictable life journey where we totally have no idea about which direction to choose. No matter what our decision is, we should not turn back, but face the music and go ahead instead. I am this kind of girl who always does try without regretting, one example is how I dealt with my love.  相似文献   

15.
王菲 《华章》2007,(12):273-273
Migration occurs behind a variety of reasons and has a great effect on the whole world. People may migrate in order to improve their economic situation, or in order to escape civil strife, persecution, and environmental disasters. The impact of migration is complex, bringing both benefits anddisadvantages. This paper briefly talks about the causes of migration, the allocation of benefits, and the ways in which individual countries and the international community deal with this important subject.  相似文献   

16.
裴水妹 《华章》2007,(11):196
Sister Carrie is one of the most controversial characters in American literature.Thought as a "fallen woman" firstly,she was defined as a "new woman" by some critics later. However, by digging into the motivaton behind the whole process of Carrie's "success", the relationship between Carrie and her creator (the author), the social conditions of then American, it can be found that Carrie has never been free-standing on her thought and she has never found her real-sdf even after becoming a famous actress. In a society dominated by mass consumerism Carrie is only an adherent of her own desires. She also is a representative of all those country girls flooded into cities, a symbol and a sacrifice of the urbanization of America in a time countryside was overcome by cities.  相似文献   

17.
18.
1.IntroductionOne-cyclecontrolmethod,whichwasproposedaboutonedecadeago[1],hasbecomeanattractivemethodinspecialfieldssuchaspowerfactorcorrection[2-6],switchingamplifiers[7,8],etc.Themainideaofthiscontrollerisbasedonintegrationofdiodevoltageinone-cycleandforcesittobeexactlyequaltothereferencevalue.Themainadvantageofthiscontrollerisitsrealtimeabilitytorejectthevariationofinputvoltage[1].Despitethisgreatability,ithasnogoodperformancesinrejectingofloaddisturbanceandfollowingreferencecommands.Espec…  相似文献   

19.
《海外英语》2007,(4):8-9
城堡, 是欧洲典型的建筑之一, 每个城堡都有一个美丽的传说或是一段历史。从本期开始, 我们将推出“城堡之旅”, 带各位读者去浏览、观赏欧洲各地的城堡, 开始一段文化与历史的旅途!  相似文献   

20.
During interview with English majors, it was found that a majority of students expressed disappointment with their experience of English literature classes. Students' dislike of learning English literature appears to be the major problem of teaching English literature in China. Reader response approach is a good way to solve this problem. In this paper, I explain the rationale behind the reader response approach, such as its origin, definition, features, assumptions, and strategies. Then I illustrate how reader response approach works as a teaching strategy by presenting several teaching models. At last I evaluate its usefuiness for teachers and present the advantages of reader response approach in Chinese context.  相似文献   

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